Question

} The zeroes of x2 – kx + 6 are in the ratio 3:2, find k.​

Answer 1

Answer:

Step-by-step explanation:

x² - kx +6 is the polynomial.

let the zeroes be Ф and ∅

therefore given , Ф/∅ = 3/2

Ф = 3∅/2

now , product of zeroes = c/a = 6/1 =Фx∅

⇒ 6 = 3∅²/2

⇒ ∅² = 4

therefore ∅ = 2

so, Ф = 3

so, putting the value of the zero in the equation ,

3² - 3k + 6 = 0

⇒ -3k = -15

⇒ k = 5

even if we put 2 in the place of x , we will get k = 5 ( you can check it )

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