Math, asked by digiprem, 2 months ago

the zeros are given form a quadratic polynomial
(2 -  \sqrt{3)} (2 +  \sqrt{3} )

Answers

Answered by mehak8274
0

Answer:

sum of zeroes = ( 2 + √ 3 ) ( 2 - √ 3 )

= 0

product of zeroes = ( 2 + √3 ) ( 2 - √3 )

= ( 2 ) ^2 - ( √ 3 ) ^ 2

= 4 - 3 = 1

quadratic polynomial = x sq. - sum of zeroes × x + product of zeroes

= x sq - 0x + 1

= x sq. + 1

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