Question

The zeros of a quaddatic polynomial are 4 and 3 which are they
And the options are
A: x²+7x-12
B:x²-7x-12
C:x²+7x+12
D:x²-7x-12

Answer 1

Answer:

Step-by-step explanation:

(x - 3)(x - 4) = x^2 - 7x + 12.

the options are all wrong

Answer 2

Step-by-step explanation:

D:x²-7x-12

x²-7x+12

➜x²-3x-4x+12

➜x(x-3)+-4(x-3)

➜(x-3)(x-4)