Question

The zeros of polynmial p(x) = 3x^2-1 are *​

Answer 1

Answer:

p(x)=3x^2-1

p(x)=(√3x)^2-(1)^2

p(x)=(√3x-1)(√3x+1)

if p(x) is zeros...then

(√3x-1)(√3x+1)=0

(√3x-1)=0 & (√3x+1)=0

x=1/√3 & x= -1/√3