Question

the zeros of polynomial x2-18x + 81​

Answer 1

p(x) =0

p(x)=2x-18x+81

2x-18x+81=0

16x+81=0 ............. (1)

16x= -81

x= -81/16

put the value of x in (1)

16x+81 =0

16 × -81/16 +81 = 0

-81 +81 =0

hope it will help you