Question

the zeros of polynomial x2-5x+6 are a) (-1,0) b)(4,5) c)(3,2) d)none of these ​

Answer 1

${x}^{2} - 5x + 6$

$\blue { \boxed{\bf roots =  \frac{ - b± \sqrt{ {b}^{2} - 4ac } }{2a} }}$

$\implies \sf roots =  \frac{ - (- 5)± \sqrt{ {( - 5)}^{2} - 4(1)(6) } }{2(1)}$

$\implies \sf roots =  \frac{ 5± \sqrt{ 25- 24}}{2}$

$\implies \sf roots =  \frac{ 5± \sqrt{ 1}}{2}$

$\implies \sf roots =  \frac{ 5± 1}{2}$

$\orange{ \therefore \sf roots(zeroes \: of \: polynomial) =  (3,2)}\\ \sf option(c)$