Question

The zeros of quadratic polynomial 4x²-9 is

Answer 1

Answer:

The zeros are $\frac{3}{2}$ and $-\frac{3}{2}$

Step-by-step explanation:

We have,

$4x^2-9=(2x)^2-3^2=(2x+3)(2x-3)$

Now

$2x+3$ will be zero, when $x=-\frac{3}{2}$

and $2x-3$ will be zero, when $x=\frac{3}{2}$