Question

the zeros of quadratic polynomial 6x square - 3 are ......... and .........​

Answer 1

Answer:

0 and 1/2............

Answer 2

$6 {x}^{2} - 3 = 0 \\ 6 {x}^{2} = 3 \\ {x}^{2} = \frac{3}{6}$

squaring both the side

$\sqrt{ {x}^{2} } = \sqrt{ \frac{3}{6} }$

$x = + \sqrt{ \frac{1}{2} } \\ x = - \sqrt{ \frac{1}{2} }$