Question

The zeros of quadratic polynomial x^2-18x+81 are
(a) both negative
(b) both positive s one negative
(c) both positive and unequal
(d) both equal and positive

Answer 1

D is a right answer of questions

Answer 2

Concept Introduction: Quadratic Equations are very special equation.

Given:

We have been Given:

${x}^{2} - 18x + 81 = 0$

To Find:

We have to Find: The Results of the Quadratic Equation will be:

1. Both Negative.
2. Both Positive and One Negative.
3. Both Positive and Unequal.
4. Both Equal and Positive.

Solution:

According to the Problem, Solver the equation first,

${x}^{2} - 18x + 81 = 0 \\ {x}^{2} - 9x - 9x + 81 = 0 \\ x(x - 9) - 9(x - 9) = 0 \\ ( x - 9)(x - 9) = 0$

therefore

$x = 9$

Since, both the results are Equal and Positive , therefore the correct option is Option No. 4.

Final Answer: The results of the given Quadratic Equation are Equal and Positive.

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