Question

the zeros of quadratic polynomial x^2-25x+156​

Answer 1

Step-by-step explanation:

x^2-25x+156=0

x^2-13x-12x+156=0

x(x-13)-12(x-13)=0

(x-13)(x-12)=0

Zeroes are:12 and 13.

Answer 2

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