Question

the zeros of quadratic polynomial x square - 27 are​

Answer 1

Step-by-step explanation:

p(x)=x^2-27

now p(x) =0

\begin{gathered} = x {}^{2} - 27 = 0 \\ = x {}^{2} = 27 \\ = x = + - \sqrt{27} \\ + 3 \sqrt{3 } \\ - 3 \sqrt{3} \end{gathered}

=x

2

−27=0

=x

2

=27

=x=+−

27

+3

3

−3

3