Question

the zeros of quadratic polynomial X square + 4 x + k are alpha and beta evaluate the values of k if alpha plus 2 beta -1​

Answer 1

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given that  

 

α+β = αβ

where α and β are the roots of the equation  x² - (k-6)x +(2k +1) = 0  

solution:-

we know that;

α+β = - (coefficient of x )/( coefficient of x² )  

=  

and αβ = (constant term)/(coefficient of x²)

=

in the question it is given that

         α+β = αβ

=> - (coefficient of x )/( coefficient of x² )  =(constant term)/(coefficient of x²)

=>    -{-(k -6) } / 1 = (2k +1) / 1

=>     (k - 6) = 2k +1  

=>     2k - k  = -6 -1  

=>     k = - 7answer

Answer 2

Step-by-step explanation:

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