Question

the zeros of the polynomial (3x^2-12)are

Answer 1

Answer:

2 is the only one zero

Step-by-step explanation:

let (3x^2-12)=0

3x^2=12

x^2=12/3

x^2=4

x=√4

x=√(2)^2

square root gets cancel

so x=2

Answer 2

Step-by-step explanation:

3x²−12=0

3x²=12

Divide each term by 3and simplify.

x2=4

Take the squareroot of both sides of the equationto eliminate the exponent on the left side.

x=±√4

The complete solution is the result of both the positive and negative portions of the solution.

x=2,−2