Question

the zeros of the polynomial 3x square + 11 x - 4 are​

Answer 1

Given equation

$3x^{2} +11x-4=0$

Solving, we get,

$3x^{2} +11x-4=0$

$\implies 3x^{2} +12x-x-4=0$

$\implies 3x(x+4)-1(x+4)=0$

$\implies (3x-1)(x+4)=0$

Now,

$3x-1=0$

$\implies x = \dfrac{1}{3}$

$x+4=0$

$\implies x = -4$

$\boxed{\boxed{\bold{Therefore, \ the \ zeroes \ of \ the \ polynomial \ are \ \dfrac{1}{3} \ and \ -4}}}}}$

                                                       

Answer 2

Solutions:

3x² + 11x - 4 = 0

3x² + 12x - x = 0

3x(x + 4) - 1(x + 4) = 0

(3x + 4) (x + 4) = 0

3x - 1 = 0

x = 1/3

x + 4 = 0

x = -4

silentlover45.❤️