The zeros of the polynomial 7x2-11x/3-2/3
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equation would be like this
so multiply 3 in this polynomial we get
21x²-11x-2
21x²-14x+3x-2
7x(3x-2)+1(3x-2)
(7x+1)(3x-2)
so the zeroes are
x=(-1)/7 x=2/3
I hope you would like my answer.
so multiply 3 in this polynomial we get
21x²-11x-2
21x²-14x+3x-2
7x(3x-2)+1(3x-2)
(7x+1)(3x-2)
so the zeroes are
x=(-1)/7 x=2/3
I hope you would like my answer.
rushi51:
Thank you so much
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