Math, asked by lakshmisri499, 1 month ago

the zeros of the polynomial f (x) =x power 3+8 is

Answers

Answered by swamiraghuram

0

Answer:

zeroes of the equation x^3 +8 are

x1 = -2

x2 = 1 + i * 1.73205

x3 = 1 - i * 1.73205

where -2 is real solution and x2,x3 are imaginary solutions

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