the zeros of the polynomial m^3 -3m^2+m+1 are a-b , a , a+b , find a and b
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Step-by-step explanation:
The given polynomial is
p(m)= m³-3m²+m+1.
So sum of the zeroes=a-b+a+a+b=-(-3)/1=3
=> 3a=3
=> a=3/3
=> a=1
(a-b)a+a(a+b)+(a-b)(a+b)=1
=> a²-ab+a²+ab+a²-b²=1
=> 3a²-b²=1
=>1×3-b²=1
=> b²=3-1=2
=> b=±√2
So the value of a=1 and b=±√2.(answer)
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