Question

the
zeros of the polynomial p(x)=2x^3+5x-12​

Answer 1

Step-by-step explanation:

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Answer 2

Given

$2x^{2} +5x-12=0$

Solving, we get,

$2x^{2} +5x-12=0$

$\implies 2x^{2} +8x-3x-12=0$

$\implies 2x(x+4)-3(x+4)=0$

$\implies (2x-3)(x+4)=0$

Now,

$2x-3=0$

$2x=3$

$\boxed{\boxed{\bold{x = \frac{3}{2}}}}}}}}$

$x+4=0$

$\boxed{\boxed{\bold{x =-4}}}}}}}$