Question

the zeros of the polynomial p(x) = x^2 - 3x are

a)0,0
b)0,3
c)0,-3
d)3,-3​

Answer 1

Answer:

b) 0,3

Step-by-step explanation:

$p(0) = 0 {}^{2} + 3(0)\\ p(0) = 0 + 3$.

hence, p(0)=0,3

HOPE IT'S HELPS YOU...

Answer 2

Answer:

hey here is your answer

B) 0,3

Step-by-step explanation:

To find zero of this P(x) Equation

{x}^{2} - 3x = p(x)x

2

−3x=p(x)

Take P(x)=0

\begin{lgathered}{x}^{2} - 3x = 0 \\ \\ \therefore \: x(x - 3) = 0 \\ \\ \therefore \: x = 0 \: \: \: \: or \: \: \: \: (x - 3) = 0\end{lgathered}

x

2

−3x=0

∴x(x−3)=0

∴x=0or(x−3)=0

First zero x= 0

\begin{lgathered}x - 3 = 0 \\ \\ \therefore \: x = 3\end{lgathered}

x−3=0

∴x=3

second zero x= 3

zeroes of P(x) = x²-3x Are 0 & 3

hope it help u