Question

The zeros of the polynomial p(x) = x^2 +x-6 are
(a) 2,3
(b)-2, 3
(c) 2.-3
(d) -2, -3​

Answer 1

Answer:

${x}^{2} + 3x - 2x - 6 = 0 \\ x(x + 3) - 2(x + 3) = 0 \\ (x + 3)(x - 2) = 0 \\ x = - 3 \\ x = 2$

which is the required ans