Question

the zeros of the polynomial p(x) =x square - 3x option a) 0,0,b)0,3,c)0,-3,d)3,-3​

Answer 1

Answer:

THE ANSWER ARE 0,3

Step-by-step explanation:

${x }^{2} - 3x = the \: zeoes \: of \: the \: polynomial \: are \: 0, 3$

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Answer 2

★ Answer :

→ For factorising we have to follow these given below steps :

Let polynomial be ax² + bx + c = 0

• Firstly we will multiply a and c.
• Then we will make the factors of their product.
• The factors must be equal to b on adding or subtracting.
• Then, we will take common.

Now, Making factors.

→ x² - 3x = 0

→ x² + 0x - 3x + 0 = 0

→ x(x + 0) -3(x - 0) = 0

[x + 0 = x - 0]

→ (x - 3)(x - 0)

→ x - 3 = 0

→ x = 3

Or

→ x - 0 = 0

→ x = 0

So, Option B is correct.