Question

The zeros of the polynomial p(x)=x2 +x-6 are-​

Answer 1

Answer:

zeros of the polynomial p(x)=x2 +x-6 are 2 and -3

Answer 2

Question :-

${x}^{2} + x - 6 = 0$

What to find = zeroes of polynomial?

Solution :-

Factorise by splitting middle term

$x {}^{2} + x - 6 = 0 \\ \\ x {}^{2} - 3x + 2x - 6 = 0 \\ \\ x(x - 3) + 2(x - 3) = 0 \\ \\ (x - 3)(x + 2) = 0$

Now split it into possible cases

$(x - 3) = 0 \\ \\ (x + 2) = 0$

Hence,

$x_1 = (3) \\ \: \: \: \: \: \: ans \\ x_2 = ( - 2)$