the zeros of the polynomial x^2-2^x-3 are (a) -3,1(b) -3,-1(c)3,-1(d) 3,1
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Given: x^2-2x-3=0
=x^2-3x+x-3=0
=x(x-3)+1(x-3)=0
=(x-3)(x+1)=0
If x-3=0 then x=3
If x+1=0 then x= -1
x=3,-1
Hence the option ‘c’ is correct
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