Math, asked by saveenrana787, 6 months ago

the zeros of the polynomial x^2-2^x-3 are (a) -3,1(b) -3,-1(c)3,-1(d) 3,1​

Answers

Answered by Shrey158
2

Answer:

Given: x^2-2x-3=0

=x^2-3x+x-3=0

=x(x-3)+1(x-3)=0

=(x-3)(x+1)=0

If x-3=0 then x=3

If x+1=0 then x= -1

x=3,-1

Hence the option ‘c’ is correct

Similar questions