Question

the zeros of the polynomial x^2 -root2x -12 are a) 2,-root2 b) 3root2,-2root2 c) -3root2,2root2 d)3root2 ,2root2​

Answer 1

Answer:

option b.

Step-by-step explanation:

x={-b+-√(b^2-4ac)}/2a

x=[-(-√2+-√{(√-2)^2-4×1×(-12)}]/2×1

x={√2+-√(2+48)}/2

x=(√2+-√50)/2

x=(√2+-5√2)/2

x={√2(1+-5)}/2

x={√2(-4)}/2=-2√2,

x={√2(6)}/2=3√2.