the zeros of the polynomial x^2(x-1)
![x^2(x-1) x^2(x-1)](https://tex.z-dn.net/?f=x%5E2%28x-1%29)
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Answer:
x³-x²
Step-by-step explanation:
because when multiple x² to x-1 we get
(x²×x)-(x²×1)
x³-x²
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