Question

The zeros of the polynomial X square + 7 x + 10 are​

Answer 1

$\sf x²+7x+10=0$

$\sf x²+5x+2x+10=0$

$\sf x(x+5)+2(x+5)=0$

$\sf (x+2)=0 \:\: or \:\:(x+5)=0$

$\sf x=-2 \:\: or\:\: x=-5$

Answer 2

☯GIVEN :

• $\bf {x^2 +7x +10}$

☯TO FIND :

• The zeros of the quadratic polynomial.

➲SOLUTION :

$:\implies \sf{x^2 +7x +10 = 0}$

• By middle term splitting :

$:\implies \sf{x^2+2x + 5x+10= 0}$

$:\implies \sf{x \bigg(x +2 \bigg)+ 5\bigg(x+ 2\bigg) = 0}$

$:\implies \sf{\bigg(x+2 \bigg) \bigg(x + 5\bigg) = 0}$

$:\implies \sf{\bigg(x+2 \bigg) = 0 \: , \: \bigg(x + 5\bigg) = 0}$

$:\implies\sf{x = 0 - 2 \: , \: x = 0 - 5}$

$\to\underline{\huge{\boxed{\blue{\frak{x = -2\: , \: x = -5}}}}}$

$\huge{\green{ \therefore}}$ The zeros of the quadratic polynomial are -2 and -5.