Question

The zeros of the polynomial
X²+1/6x-2
​

Answer 1

Answer:

000

Step-by-step explanation:

Answer 2

Answer:

-32

Step-by-step explanation:

Polynomial : x2+16x−2x2+16x−2

Comparing with standard equation, we get

a = 1, b = 1616  , c = -2

To find zero, equate it with 0

=>x2+16x−2=0=>x2+16x−2=0

Multiply by 6

=>6x2+x−12=0=>6x2+x−12=0

=>6x2+9x−8x−12=0=>6x2+9x−8x−12=0

=> 3x(2x+3) - 4(2x+3) = 0

=> (2x+3)(3x-4) = 0

2x+3 = 0   Or  3x-4 = 0

=> x = −32 or 43−32 or 43

We know

Sum of zeroes = −ba−ba

=>  −32+43=−16−32+43=−16

=> −9+86=−16−9+86=−16

=> −16=−16−16=−16

Also

Product of zeroes = caca

=> −32