Question

the zeros of the polynomial x²-49 will be

Answer 1

Answer:

${x}^{2} - 49 = 0 \\ \\ = > {x}^{2} = 49 \\ \\ = > x = + \: or \: - \: \sqrt{49} \\ \\ = > x = + \: or \: - \: 7 \\ \\ roots \: are \: either \\ \\ + 7 \: or \: - 7$

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Answer 2

x=0

therefore 0^2-49

= 49