the zeros of the polynomial x²-7x+12 are
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Answered by
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Answer: 3,4
Step-by-step explanation:
x^2 - 7x + 12
=> x^2 -4x -3x + 12 (by middle term splitting)
=> x(x-4) -3 (x-4)
=> (x-4)(x-3)
Hope this helped ^_^
Answered by
0
Hey mate here is your answer.
x^2 - 7x + 12
=> x^2 -4x -3x + 12 (by middle term splitting)
=> x(x-4) -3 (x-4)
=> (x-4)(x-3)
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