Question

the zeros of the quadratic polynomial (a² + 9) x² + ax - 13 are reciprocal to each other find the value of a​

Answer 1

The given a polynomial first Zeros = X

second Zero = 1/X

we know that

product of zeroes = c/a

$x \times \frac{1}{x} = \frac{ 1 3}{ {a}^{2} + 9} \\ 1 = \frac{ 13}{ {a}^{2} + 9} \\ {a}^{2} + 9 = 13 \\ a = \frac{ + }{ - } 4$