The zerosof xsquare+(a+1) are 2 and -3 then a is
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ans :- -5 , -10
Step-by-step explanation:
the quadratic equation :-. X^2 +(a+1)
the zeroes are = 2 , -3
Case 1 :-. substitute 2 in eq 1
2×2 + a + 1 = 0
4 + a + 1 = 0
a = -5
Case 2 :- substitute-3 in eq 1
-3 × -3 + a + 1 = 0
9 + 1 + a = 0
a = -10
therefore the values of a is -5 , -10
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