The Zn product obtained by calculation is 2.2383 joule. If efficiency of cell is 90% how much product will be obtained experimentally ? (a) 2.014 mole (b) 2.14 mole (c) 2.214 mole (d) 2.04 mol
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Answer:
Correct option is
A
0.65 g
Zn+H
2
SO
4
→ZnSO
4
+H
2
At STP 224 mL of hydrogen corresponds to
1000×22.4
224
=0.01 moles of hydrogen. They will be produced from the reaction of 0.01 mole of Zn with 0.01 mole of sulphuric acid. Hence, the mass of zinc required is 65.38×0.01=0.65 g.
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