Question

The10,18 term of an a.p are 41,73 are respectiv
ly find the27th term

Answer 1

Answer:

we know that,

tn=a+(n-1)d,

41=a+(10-1)d,------>eqn1

73=a+(18-1)d,------>eqn2,

solving eqn 1:& eqn2,

we get,d=4,a=5,

therefore,

27th term =5+(27-1)4=109

2nd method :

given,

10&18 term in Ap

so,d=(73-41)/8=4,

41=a+(10-1)4,

a=5,

then,

t27=5+(26)4=109.

Hope it helps u...