Question

Thedigit at tens place of a two git number is two tomes the digit at ones place if digits are reverded the becomes 18less then the original number find number

Answer 1

Answer:

THE ORIGINAL NUMBER IS 42.

Step-by-step explanation:

LET THE ONE'S DIGIT BE x

THEN , TEN'S DIGIT = 2 x

SINCE, THIS IN THE ARRANGEMENT ,

THE NUMBER = 10 (2x) + x

20x + x = 21 x

WHEN THE NUMBERS ARE REVERSED,

THE TEN'S DIGIT = x

ONE'S DIGIT = 2 x

SINCE, THIS IS THE ARRANGEMENT .

THE NUMBER = 10 ( x ) + 2x

= 10x+ 2x = 12x

ACCORDING TO THE QUESTION ,

21x - 18 = 12x

21x  -  12 x = 18

9x = 18

x = 18 / 9 = 2

SO, x ( UNIT'S DIGIT = x )  ,

ONES DIGIT = 2 .

TEN'S DIGIT = 2 * 2 = 4

SO, THE NUMBER = 4 (10) + 2

42

SO, THE ORIGINAL NUMBER = 42.

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