Question

Thee times the smallest of the three consecutive odd number decreased by 7 equal twice the largest one find numberT

Answer 1

let the consecutive odd integers be (2x+1), (2x+3)  and (2x+5)

the smallest number is 2x+1 and the largest number is 2x+5

given that,

3(2x+1) - 7 = 2(2x+5)

6x + 3 -7 = 4x +10

2x = 14

x = 7

as the question you gave is not clear, i'm just giving all the values. you mentioned that we have to find T, but i don't know what you took as T so i'm giving all the values

smallest value is 15

middle number is 17

largest value is 19