Question

∅ = Theeta
Find distance b/w
(Cos∅,-sin∅) (sin∅,-Cos∅)
​

Answer 1

Answer:

BY DISTANCE FORMULA

$\sqrt{(x 2 - x1) ^{2} + (y2 - y1)^{2} }$

√sinø-cosø-cosø+sinø

√-2cosø is distance

Answer 2

Answer:

Let cos∅ be x1

- sin∅ be y1

similarly they became x2,y2

By distance formula

$\sqrt{}( x {}^{2} - y {}^{2} ) + (x { }^{2} - y {}^{2} )$

Now we put values,

√(cos²∅+ sin²∅) + (sin²∅ + Cos²∅)

=√ (1)² + (1)²

= √1 + 1

= √2