their are 3 cats of different weight. first and second cats weigh 7kg altogether. second and third weigh 8kg altogether. first and third weigh 11th altogether. what is the weight of each cat
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let the weight of first cat be x
second cant be y
third cat be z
there fore2(x+y+z)=11+7+8
x+y+z=13
x+y=7
7+z=13
z=6
y+z=8
6+y=8
y=2
x+2=7
x=5
x,y,z=5,2,6
second cant be y
third cat be z
there fore2(x+y+z)=11+7+8
x+y+z=13
x+y=7
7+z=13
z=6
y+z=8
6+y=8
y=2
x+2=7
x=5
x,y,z=5,2,6
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Let the weight of 1st, 2nd and 3rd cat be x, y, z respectively.
According to the question --
x + y = 7 => x = 7 - y
y + z = 8 ...........(i)
x + z = 11 ...........(ii)
Now putting the value of x in (ii),
7 - y + z = 11
- y + z = 4 ..........(iii)
Now subtracting (iii) from (ii) we get,
z = 6 kg
Now putting the value of z in (iii),
- y = 4 - 6
y = 2 kg
x = 7 - 2 = 5kg
So weight of 1st cat = 5 kg, 2nd cat = 2kg, 3rd cat = 6kg
According to the question --
x + y = 7 => x = 7 - y
y + z = 8 ...........(i)
x + z = 11 ...........(ii)
Now putting the value of x in (ii),
7 - y + z = 11
- y + z = 4 ..........(iii)
Now subtracting (iii) from (ii) we get,
z = 6 kg
Now putting the value of z in (iii),
- y = 4 - 6
y = 2 kg
x = 7 - 2 = 5kg
So weight of 1st cat = 5 kg, 2nd cat = 2kg, 3rd cat = 6kg
x + y = 7 => x = 7 - y
y + z = 8 ...........(i)
x + z = 11 ...........(ii)
Now putting the value of x in (ii),
7 - y + z = 11
- y + z = 4 ..........(iii)
Now subtracting (iii) from (ii) we get,
z = 6 kg
Now putting the value of z in (iii),
- y = 4 - 6
y = 2 kg
x = 7 - 2 = 5kg
So weight of 1st cat = 5 kg, 2nd cat = 2kg, 3rd cat = 6kg
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