Question

their difference is 14". Find the two angles. In lia The figure shows an equilateral triangle with its sides as indicated. Find the length of each side of the triangle
(2x-7)cm
(y+5)cm
(X+y+9) cm
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Answer 1

Multiplying (2) by 2 and subtracting (1) from it, we get 3x=18. Hence x=6.

Multiplying (2) by 2 and subtracting (1) from it, we get 3x=18. Hence x=6.Finally 2y=2x−8=2(6)−8=12−8=4. Hence y=2.

Multiplying (2) by 2 and subtracting (1) from it, we get 3x=18. Hence x=6.Finally 2y=2x−8=2(6)−8=12−8=4. Hence y=2.Thus the side of the triangle is x+y−1=6+2−1=7cm. Its perimeter is 3×7=21 cm.

Multiplying (2) by 2 and subtracting (1) from it, we get 3x=18. Hence x=6.Finally 2y=2x−8=2(6)−8=12−8=4. Hence y=2.Thus the side of the triangle is x+y−1=6+2−1=7cm. Its perimeter is 3×7=21 cm.Was this answer helpful?

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