Math, asked by rajeshtiwary6735, 10 months ago

their rivers of length 16 28 and 36 need to be cut into pieces of this same length in such a way that nothing is left what will be the greatest possible length

Answers

Answered by alfredoshajumercy

0

Answer:

Maximum length of each piece = HCF of 16 & 20

16 = 2 *2 *2 *2

20 = 2* 2* 5

So, HCF = 2² = 4

So, length of each piece = 4 m

& we will have 9 such piece

Step-by-step explanation:

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