thelegs of a right angled triangle are in the ratio 4:3 and its area is 4056cm square find the length of its legs
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Let the 2 legs be 4x and 3x.
Given, Area = 4056 cm^2
therefore , 4056=1/2*4x*3x
=6x^2
676=x^2
x=√676=26.
therefore the two sides:- 4x=26*4=104cm
3x=3*26=78cm
hypotenuse:- √104^2 +78^2.
=130 cm.........
Given, Area = 4056 cm^2
therefore , 4056=1/2*4x*3x
=6x^2
676=x^2
x=√676=26.
therefore the two sides:- 4x=26*4=104cm
3x=3*26=78cm
hypotenuse:- √104^2 +78^2.
=130 cm.........
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