Question

Thelengthandbreadthofarectanglulargardenare

96cmand 74cmrespectively.Apath4cmwideistobe

constructed outside and around the garden.Find the area of

the path.​

Answer 1

$\Huge\mathbf\colorbox{gold}{{\color{black}{AnSwEr࿐}}}$

⠀

$\huge\color{gold}{\textbf{\textsf{GIVEN :}}}$

$\bigstar\bf{The \: length \: of \: rectangular \: garden = 96 \: cm.}$

$\bigstar\bf{The \: breadth \: of \: rectangular \: garden = 74 \: cm.}$

$\bigstar\bf{A \: path \: of \: 4 \: cm \: is \: to \: be \: constructed.}$

⠀

$\huge\color{gold}{\textbf{\textsf{TO FIND :}}}$

$\bigstar\bf{Find \: the \: area \: of \: the \: path.}$

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$\huge\color{gold}{\textbf{\textsf{SOLUTION :}}}$

$\bigstar\bf{Outer \: length }$

$\bf{→96 + 4 + 4} \\ \bf{→104}$

$\bigstar\bf{Outer \: breadth }$

$\bf{→74 + 4 + 4} \\ \bf{→82}$

⠀

$\bigstar\bf{Area \: of \: path = Area \: of \: outer \: rectangle - Area \: of \: inner \: rectangle}$

$\bf{→(104 \times 82) - (96 \times 74)} \\ \bf{→8528 - 7104} \\ \bf{→1424 \: {cm}^{2} }$

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$\boxed{{\bf{Hence, \: the \: area \: of \: the \: path \: is \: 1424 \: {cm}^{2}. }}}$

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Hope it Helps Buddy ♥️

Answer 2

$\Huge\mathbf\colorbox{gold}{{\color{black}{AnSwEr࿐}}}$

⠀

$\huge\color{gold}{\textbf{\textsf{GIVEN :}}}$

$\bigstar\bf{The \: length \: of \: rectangular \: garden = 96 \: cm.}$

$\bigstar\bf{The \: breadth \: of \: rectangular \: garden = 74 \: cm.}$

$\bigstar\bf{A \: path \: of \: 4 \: cm \: is \: to \: be \: constructed.}$

⠀

$\huge\color{gold}{\textbf{\textsf{TO FIND :}}}$

$\bigstar\bf{Find \: the \: area \: of \: the \: path.}$

⠀

$\huge\color{gold}{\textbf{\textsf{SOLUTION :}}}$

$\bigstar\bf{Outer \: length }$

$\begin{gathered}\bf{→96 + 4 + 4} \\ \bf{→104}\end{gathered}$

$\bigstar\bf{Outer \: breadth }$

$\begin{gathered}\bf{→74 + 4 + 4} \\ \bf{→82}\end{gathered}$

⠀

$\bigstar\bf{Area \: of \: path = Area \: of \: outer \: rectangle - Area \: of \: inner \: rectange}$

$\begin{gathered}\bf{→(104 \times 82) - (96 \times 74)} \\ \bf{→8528 - 7104} \\ \bf{→1424 \: {cm}^{2} }\end{gathered}$

⠀

$\boxed{{\bf{Hence, \: the \: area \: of \: the \: path \: is \: 1424 \: {cm}^{2}. }}}$