then 17th term of an a.p. is 7 times more than its 10th term find the first term and the common difference if a10=10
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Answer:
We know that, for an A.P series
an = a+(n−1)d
a17 = a+(17−1)d
a17 = a +16d
In the same way,
a10 = a+9d
As it is given in the question,
a17 − a10 = 7
Therefore,
(a +16d)−(a+9d) = 7
7d = 7
d = 1
Therefore, the common difference is 1.
Step-by-step explanation:
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