then (a,b) =?
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THE ANSWER IS HERE,
= > \: \frac{3 + \sqrt{7} }{3 - \sqrt{7} }
= > \: \frac{3 + \sqrt{7} }{3 - \sqrt{7} } \times \frac{3 + \sqrt{7} }{3 + \sqrt{7} }
= > \: \: \frac{( {3 + \sqrt{7} )}^{2} }{ {3}^{2} - { \sqrt{7} }^{2} }
= > \: \frac{9 + 7 + 6 \sqrt{7} }{2}
= > \: \frac{16 + 6 \sqrt{7} }{2}
= > \: 8 + 3 \sqrt{7} .
From the question,
= > \: 8 + 3 \sqrt{7} = a + b \sqrt{7}
= > \: a = 8 \:
= > \: b = 3.
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