Question

then angle between the two vectors A​

Answer 1

Answer:

zero degree

Explanation:

since the vectors are parallel to each other

Answer 2

Given:

$\star \vec{A} = 3 \hat{i} + 4 \hat{j} + 5 \hat{k} \\ \\ \star \vec{ B} = 3 \hat{i} + 4 \hat{j} + 5 \hat{k}$

To find :

• Angle between A and B .

Solution :

• As we know that ,

$\star \: \boxed{ \bold{ \cos \theta= \frac{ \vec{A}. \vec{B}}{ | \vec{A}| | \vec{B}| } }}$

$\implies \cos \theta \: = \frac{( 3 \hat{i} + 4 \hat{j} + 5 \hat{k})( 3 \hat{i} + 4 \hat{j} + 5 \hat{k})}{( \sqrt{ {3}^{2} + {4}^{2} + {5}^{2} )}( \sqrt{ {3}^{2} + {4}^{2} + {5}^{2} )} } \\ \\ \implies \cos \theta \: = \frac{9 + 16 + 25}{ \sqrt{50} \sqrt{50} } \\ \\ \implies \cos \theta \: = \frac{50}{50} \\ \\ \implies \cos \theta \: = 1 \\ \\ \implies \: \theta = 0 \degree$

Hence ,the angle is 0°.