Question

then find out sequence.
Fifth and tweveth term of an arithmetic progression are 1
and 29 respectively then find out its 47" term.​

Answer 1

Answer:

a₄₇ = 169

Step-by-step explanation:

a5 = 1  and a12 = 29

so a + 4d = 1   is equation 1

and, a + 11d = 29 equation 2

now eliminate a to find the value of d

a + 11d - (a + 4d) = 29 - 1

a + 11d -a - 4d = 28

11d - 4d =  28

7d = 28

d =  4

Now, putting the value of d in equation 1 we get,

a + 4d = 1

a + 4(4) = 1

a = 1 - 4(4)

a = 1 - 16

a = -15

so a₄₇ = a +  46d

⇒ a₄₇ = -15 + 46(4)

⇒ a₄₇ = -15 + 184

⇒ a₄₇ = 169