then
In AABC, if a= 2, b=3 and sin A = 2/3, then
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0
Answer:
In △ABC a=2,b=3 and sinA=2/3
By applying sine law
sinA
a
=
sinB
b
=
sinC
c
→
2/3
2
=
sinB
3
→sinB=1⇒B=
2
π
.
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