then nth term of an a.p is 6n+2. find its common difference.
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Answered by
2
substituting the value with 1,2 and other numbers we get an AP whose vommon difference will be 8
mastermindankit123:
sorry 6
wii be common difference
first term 8 and second term 14
hence common difference will be 6
would u please typ again
Put n=1,2,3
a1= 6×1+2=8
a2=6×2+2=14
a3=6×3+2=20
Therefore, AP=8,14,20....
So, d=6
a1= 6×1+2=8
a2=6×2+2=14
a3=6×3+2=20
Therefore, AP=8,14,20....
So, d=6
Answered by
1
here is your answer.....
Put n=1,2,3
a1= 6×1+2=8
a2=6×2+2=14
a3=6×3+2=20
Therefore, AP=8,14,20....
So, d=6
a1= 6×1+2=8
a2=6×2+2=14
a3=6×3+2=20
Therefore, AP=8,14,20....
So, d=6
Put n=1,2,3
a1= 6×1+2=8
a2=6×2+2=14
a3=6×3+2=20
Therefore, AP=8,14,20....
So, d=6
a1= 6×1+2=8
a2=6×2+2=14
a3=6×3+2=20
Therefore, AP=8,14,20....
So, d=6
Put n=1,2,3
a1= 6×1+2=8
a2=6×2+2=14
a3=6×3+2=20
Therefore, AP=8,14,20....
So, d=6
a1= 6×1+2=8
a2=6×2+2=14
a3=6×3+2=20
Therefore, AP=8,14,20....
So, d=6
right
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two tangents PA and PB are drawn to the circle O , such that angel APB=120 degree. provw that OP= 2AP
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