Question

then prove a - b = 1​

Answer 1

Answer:

$(\ \ {a}^{b} \times {3}^{2} \times ( {3 \times \frac{ - b}{2} )}^{ - 2} - {27}^{b} ) \div {3}^{3a} \times {2}^{3} = 1 \div 27 \\( {a}^{b} \times {3}^{2} \times {3}^{b} - {27}^{b} ) \div {3}^{3a} \times {2}^{3} = 1 \div {3}^{3} \\ {(a}^{b} \times {3}^{2} \times {3}^{b}(1 - 9)) \div {3}^{3a} \times {2}^{3} = 1 \div {3}^{3} \\ ( {a}^{b} \times {3}^{2} \times ( - {24}^{b} )) \div {3}^{3a} \times {2}^{3} = 1 \div {3}^{3} \\ ( {a}^{b} \times {3}^{2 - 3a} \times ( - {24}^{b} )) \ = 1 \div ( {6}^{3} ) \\ ( { - 24a}^{b} \times {3}^{2 - 3a} ) = 1 \div ( {6}^{3} ) \\ 3( { - 8a}^{b} \times {1}^{2 - 3a} ) = 1 \div( { {2}^{3} } \times {3}^{3} ) \\ ( { - 8a}^{b} \times {1}^{2 - 3a} ) = 1 \div ( {2}^{3} \times {3}^{4})$

Step-by-step explanation:

u can solve ahead easily

pls mark branliest

pls