Question

Then prove that a = t - q upon r - p

Answer 1

hey check this out the answer

Answer 2

since x-a is common factor to both polynomials hence on putting x=a ...both polynomials will give same output...
therefore.. put x=a
${a}^{2} + pa - q = {a}^{2} + ar - t \\ pa - q = ar - t \\ a(p - r) = q - t \\ a = (q - t) \div (p - r) \\ a = (t - q) \div (r - p)$
here is ur answer.... mark as brainliest if helped