Question

then prove that AQ =1/2 ( perimeter of triangle ABC
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Answer 1

Answer:

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Answer 2

Answer:

A circle touching the side BC of ΔABC at P and AB, AC produced at Q and R respectively. Proof: Lengths of tangents drawn from an external point to a circle are equal. ⇒ AQ = AR, BQ = BP, CP = CR. ∴ AQ is the half of the perimeter of ΔABC

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